Решите уравнение 1)7x+49=0 2)12-0,6x=0 3)8k-1=4k+1 4)10c+2=40-9c

Решим по шагам.

1. $7x + 49 = 0$
   $7x = -49$ → $x = \dfrac{-49}{7} = -7$.

2. $12 - 0{,}6x = 0$
   $-0{,}6x = -12$ → $x = \dfrac{-12}{-0{,}6} = 20$.

3. $8k - 1 = 4k + 1$
   $8k - 4k = 1 + 1$ → $4k = 2$ → $k = \dfrac{2}{4} = 0{,}5$.

4. $10c + 2 = 40 - 9c$
   $10c + 9c = 40 - 2$ → $19c = 38$ → $c = \dfrac{38}{19} = 2$.

Ответ: $x=-7$; $x=20$; $k=0{,}5$; $c=2$.